A rectangle measures 6 3/4 cm by square root of 121 cm. What is the perimeter of the rectangle to the nearest tenth?

Question

asked Oct 9, 2021 170k views

2 Answers

Greg Lary · Answer 1 · 2021-10-10T10:27:38+0000

Answer:

35.5cm

Explanation:

The perimeter (P) is calculated as

P = (2 × 6.75 ) + (2 × \sqrt{121}121 )

= 13.5 + (2 × 11) = 13.5 + 22 = 35.5 cm

Scott Nichols · Answer 2 · 2021-10-16T18:52:35+0000

Answer:

35.5 cm

Explanation:

The perimeter (P) is calculated as

P = (2 × 6.75 ) + (2 ×
√(121) )

= 13.5 + (2 × 11) = 13.5 + 22 = 35.5 cm