Question

Triangle ABC has vertices at A(-5,2), B(-4,-6) and C(4,3). It is translated 1

unit left and 2 units up. What are the vertices of A'B'C'?*

Answer 1

The vertices of triangle A'B'C' after it is translated 1 unit left and 2 units up are A'(-6, 4), B'(-5, -4), and C'(3, 5).

Step-by-step explanation:

The student is asking about the result of performing a geometric translation on a triangle in the Cartesian coordinate plane. To find the new vertices after the translation of triangle ABC, we add the translation vector (-1, 2) to each of the original vertices. Here are the calculations for each vertex:

• 
  
• A' = (-5 - 1, 2 + 2) = (-6, 4)
• 
  
• B' = (-4 - 1, -6 + 2) = (-5, -4)
• 
  
• C' = (4 - 1, 3 + 2) = (3, 5)

Therefore, the new vertices of triangle A'B'C' after being translated 1 unit left and 2 units up are A'(-6, 4), B'(-5, -4), and C'(3, 5).

Answer 2

A' =(-6, 4); B' = (-5, -4); C' = (3, 5)

Step-by-step explanation:

move 1 unit left means subtracting 1 from x-coordinate

move 2 units up means adding 2 to y-coordinate

A' = (-5-1, 2+2) = (-6, 4)

B' = (-4-1, -6+2) = (-5, -4)

C' = (4-1, 3+2) = (3, 5)