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A car has a velocity of 6.23 m/s. The driver hits the gas and accelerates the car at 2.16 m/s^2. How fast is the car moving after 5.85 s?

User YLG
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1 Answer

6 votes

Recall that


v_f=v_i+at

So we have


v_f=6.23(\rm m)/(\rm s)+\left(2.16(\rm m)/(\mathrm s^2)\right)(5.85\,\mathrm s)


\implies\boxed{v_f\approx18.9(\rm m)/(\rm s)}

User RMWChaos
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