Answer:
Explanation:
I'm just going to go out on a limb here and assume that those are a set of poorly made parenthesis. This, then, would be your equation:
![x+(x)/(7)+(1)/(11)(x+(x)/(7))=60](https://img.qammunity.org/2021/formulas/mathematics/high-school/eazql9n12wif3n6uzvku278s0ymr61l5at.png)
The first thing to do is distribute through the parenthesis to get:
![x+(x)/(7)+(x)/(11)+(x)/(77)=60](https://img.qammunity.org/2021/formulas/mathematics/high-school/p5pyb924imhx5micuvlmdcyl8j0smuh296.png)
Next is to get rid of the denominators by multiplying by the LCM of 77:
which gives you:
77x + 11x + 7x + x = 4620 and
96x = 4620 so
![x=(385)/(8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/vok32ix5qwfxrrt9fcez9136z6kntyra7f.png)