Question

What is the mass of a 67 dL sample of a salt solution?

Answer 1

6733.5 g of NaCl

Step-by-step explanation:

We can assume that the salt solution is a saline solution which contains NaCl in water at 0.90%, whose density is 1.005 g/ml.

So we need to apply the density concept to solve the question.

Density = mass / volume

We convert dL to mL → 67 dL . 100mL / 1 dL = 6700 mL

Density = mass / volume

Volume . Density = mass

6700 mL . 1.005 g = 6733.5 g of NaCl