Question

Which equation describes this line?
(1, 13)
(-2, 4)

Answer 1

y =3x+10

Explanation:

`\mathrm{Line\:passing\:through\:}\left(1,\:13\right)\mathrm{,\:}\left(-2,\:4\right)\\\\(1,13)=(x_1,y_1)\\(-2,4) = (x_2,y_2)\\\\(y-13)/(x -1) = (4-13)/(-2-1)\\ \\(y-13)/(x-1) = (-9)/(-3)\\\\ -3(y-13)=-9(x-1)\\\\-3y +39 =-9x +9\\\\-3y =-9x+9-39\\\\-3y =-9x -30\\\\(-3y)/(-3) = (-9x)/(-3) - (30)/(-3) \\\\y = 3x+10`

Answer 2

y - 4 = 3 ( x + 2 )

Explanation:

so ,

( 1 , 13 ) and ( - 2 , 4 )

x1 y1 x2 y2

formulae of slope m is y2-y1

over

x2-x1

4-13

/

-2-1

-9/-3

therefore m=3

now to get the equation of line is

y-y1=m(x-x1)

y - 13 = 3 ( x - 1 )

y - 13 = 3 x - 3

y = 3 x - 3 + 13

y = 3 x + 10

y - 4 = 3 x + 6

y - 4 = 3 ( x + 2