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1 vote
(3 + 5i) + (11 -7i) Write answer in standard form a +bi

User AlessioX
by
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1 Answer

6 votes

Answer:

14-2i

Explanation:


\left(3+5i\right)+\left(11-7i\right)\\\\Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\\\=\left(3+11\right)+\left(5-7\right)i\\3+11=14\\5-7=-2\\\\=14-2i

User Fabio Gomes
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