Answer:
8 movies and 6 video games
Explanation:
Given
![Gift\ Card = \$600](https://img.qammunity.org/2021/formulas/mathematics/college/ow79wft94l5vwgd6n8gjvyy2yai48tmxrk.png)
![Movies =\ $20](https://img.qammunity.org/2021/formulas/mathematics/college/5hkrwf4727f0b7flhkem7iwjy3pl1hmmwv.png)
![Video\ Game = \$50](https://img.qammunity.org/2021/formulas/mathematics/college/w6o3wseucgs1tkazvj1lk9prntoyzjhcy0.png)
![Minimum\ Items = 13](https://img.qammunity.org/2021/formulas/mathematics/college/2m9nuhzp7hdhrewm0t55yapzl2mx0rdm69.png)
Required
Determine the items Lonnie can afford
To solve this question, we make use of trial by error method by taking the options one at a time:
Option 1: 6 movies and 4 video games
This option can not be considered because the number of items is not up to the minimum Lonnte must purchase.
Option 2: 14 movies and 7 video games
![Cost = 14 * \$20 + 7 * \$50](https://img.qammunity.org/2021/formulas/mathematics/college/9lq7zwjkkpbgvjrgblv6vxclai1zon4snz.png)
![Cost = \$280 + \$350](https://img.qammunity.org/2021/formulas/mathematics/college/fc7bijxpmnwujhakfbfv6qr1yq7h0vos61.png)
![Cost = \$630](https://img.qammunity.org/2021/formulas/mathematics/college/rjet13vjvwrktil8w0wqt0nru76p2lzk4g.png)
This option can not be considered because the cost of purchase is greater than Lonnte's worth of Gift card.
Option 3: 2 movies and 10 video games
This option can not be considered because the number of items is not up to the minimum Lonnte must purchase.
Option 4: 8 movies and 6 video games
![Cost = 8 * \$20 + 6 * \$50](https://img.qammunity.org/2021/formulas/mathematics/college/72bdjjgup44k6r3x62a82rikbb1hxuwdg1.png)
![Cost = \$160 + \$300](https://img.qammunity.org/2021/formulas/mathematics/college/fcj45qu4ydr0142d1uidpblcb7w73sguys.png)
![Cost = \$460](https://img.qammunity.org/2021/formulas/mathematics/college/5kzerel72j17dns8r6syu80xnbun1qgk59.png)
Hence, the correct option is 8 movies and 6 video games