Answer:
![(ML)/(T^2)=(ML)/(T^2)](https://img.qammunity.org/2021/formulas/engineering/college/ta39rzkfumf5nrt8jzcjxb7ckpu38pb0ed.png)
Hence it is proved that Stokes-Oseen formula is dimensionally homogenous.
Step-by-step explanation:
For equation to be dimensionally homogeneous both side of the equation must have same dimensions.
For given Equation:
F= Force, μ= viscosity, D = Diameter, V = velocity, ρ= Density
Dimensions:
![F=(ML)/(T^2)](https://img.qammunity.org/2021/formulas/engineering/college/8rw9zrq6gnknv6aq4m516t7f1dfkourhf5.png)
![\mu=(M)/(LT)](https://img.qammunity.org/2021/formulas/engineering/college/i8idczo4e3cpwqftff406rk027fh0ziuh3.png)
![D=L\\\\V=(L)/(T)\\ \\\rho=(M)/(L^3)](https://img.qammunity.org/2021/formulas/engineering/college/jb1373mzsoswk9pvloq4rp0d5nwyl48nf1.png)
Constants= 1
Now According to equation:
![(ML)/(T^2)=[(M)/(LT)][L] [(L)/(T)] + [(M)/(L^3)][(L^2)/(T^2)][L^2]](https://img.qammunity.org/2021/formulas/engineering/college/gpteol9u73xpb47jk4gta3owidvsibceni.png)
Simplifying above equation, we will get:
![(ML)/(T^2)=2*(ML)/(T^2)](https://img.qammunity.org/2021/formulas/engineering/college/y4121xyvzp9k9pfu51c0eno3ojvzetreqc.png)
Ignore "2" as it is constant with no dimensions. Now:
![(ML)/(T^2)=(ML)/(T^2)](https://img.qammunity.org/2021/formulas/engineering/college/ta39rzkfumf5nrt8jzcjxb7ckpu38pb0ed.png)
Hence it is proved that Stokes-Oseen formula is dimensionally homogenous.