Question

I need help with this algebra 2

Answer 1

(2)

Explanation:

2(2x-1) = 5x²

expand

4x - 2 = 5x²

subtract (4x-2) from both sides to make it a quadratic equation

5x² -4x + 2 = 0

plug into the quadratic formula

ax² + bx + c

`x= (-b+-√(b^2-4ac) )/(2a) \\= (-(-4)+-√((-4)^2-4(5)(2)) )/(2(5)) \\= (4+-√(16-40) )/(10) \\= (4+-√(-24) )/(10) \\\\=(4+-2i√(6(4)(-1)) )/(10) \\= (4+-2i√(6) )/(10) \\= (2+-i√(6) )/(5) \\= 2/5 +- √(6) /5 * i`

thus, the coefficient attached to i is +- √6/5, making (2) our answer

(1) is not the answer because our answer would then be

a + bi = 2/5 + √6/5 * i * i = 2/5 - √6/5, which isn't our answer