Question

light of a wavelength 600 nm shines on a soap bubble film. For what soap film thickness will destructive interference occur

Answer 1

The minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.

Step-by-step explanation:

Given;

wavelength of light, λ = 600 nm

The minimum thickness of the soap bubble for destructive interference to occur is given by;

`t = (\lambda/n)/(2)\\\\t = (\lambda)/(2n)`

where;

n is refractive index of soap film = 1.33

`t = (\lambda)/(2n) \\\\t = (600*10^(-9))/(2(1.33))\\\\t = 2.2556 *10^(-7) \ m\\\\t = 225.56 *10^(-9) \ m\\\\t = 225.56 \ nm`

Therefore, the minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.