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14 votes
14 votes
NO LINKS!! NO MULTIPLE CHOICE!!​

NO LINKS!! NO MULTIPLE CHOICE!!​-example-1
User Gaurav Thummar
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1 Answer

20 votes
20 votes

Answer:

Given points

  • A = (2, 1)
  • B = (4, 3)
  • C = (5, 3)
  • D = (6, 1)

Part (a)

See attached

Part (b)

Trapezoid

Part (c)

To dilate ABCD with a dilation center at (0,0) and a dilation factor of 4, multiply the x and y coordinates of ABCD by sf 4:

  • A' = (8, 4)
  • B' = (16, 12)
  • C' = (20, 12)
  • D' = (24, 4)

Part (d)


\begin{aligned}\textsf{Area of Trapezoid}& =(1)/(2)(a+b)h\\\implies \textsf{Area of A'B'C'D'}& =(1)/(2)((x_(D')-x_(A'))+(x_(C')-x_(B')))(y_(B')-y_(A'))\\& = (1)/(2)((24-8)+(20-16))(12-4)\\& = (1)/(2)(20)(8)\\& = 80\: \sf units^2\end{aligned}

NO LINKS!! NO MULTIPLE CHOICE!!​-example-1
User Mike Tsayper
by
3.1k points