Question

What is the speed of an electron that has been accelerated to the point at which its total energy is 10.5 times its rest mass

Answer 1

0.995*c= 2.98*10^8m/s

Step-by-step explanation:

Using

E= mc²

10.5 mc² = mc²/√1-v²/c²

So

1-v²/c²=( 1/10.5)²

V= √1-0.009c

V= 0.995 x 3E8m/s

= 2.98*10^8m/s