Question

Consider the reaction below. If the concentration of B decreases by 0.068 M, what will be the change in concentration for C? 3A(g)+4B(g)⇋5C(g)

Answer 1

.085 M .

Step-by-step explanation:

3A(g) +4B(g) ⇋ 5C(g)

4 moles of B reacts with A to form 5 moles of C

.068 moles of B will reacts with A to form 5 x .068 / 4 moles of C

Moles of C formed

= 5 x .068 / 4

= .085 moles .