Question

Marleny is creating a game of chance for her family. She has 5 different colored marbles in a bag: blue, red, yellow, white, and black. She decided that blue is the winning color. If a player chooses any other color, they lose 2 points. How many points should the blue marble be worth for the game to be fair?

4
6
8
10

Answer 1

The blue marble should be worth 8 points for the game to be fair.

Step-by-step explanation:

To determine how many points the blue marble should be worth for the game to be fair, we need to calculate the probability of choosing the blue marble and the expected value. Since there are 5 marbles in total and 1 blue marble, the probability of choosing blue is 1/5. The expected value is calculated by multiplying the probability of winning (1/5) by the points awarded for winning (let's call it x) and subtracting the probability of losing (4/5) multiplied by the points deducted for losing (2).

So the equation is: (1/5)x - (4/5)(2) = 0. We can solve for x by multiplying through by 5 to eliminate the fractions and then solving the resulting equation: x - 8 = 0. Add 8 to both sides and we get x = 8. Therefore, the blue marble should be worth 8 points for the game to be fair.

Answer 2

The answer is four because if you lose two from the four you had you will still have a least 2 hope This helped