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5 votes
1. -10=xy+z, solve for x please? 2. h-4/j =k, solve for j please?​

User OneWinged
by
8.5k points

2 Answers

5 votes

Answer:


\huge \boxed{x= (-10-z)/(y) } \\\\\\\\ \huge \boxed{j=(4)/(h-k) }


\rule[225]{225}{2}

Explanation:

Solving for x:


-10=xy+z

Subtracting z from both sides:


-10-z=xy

Divding both sides by y:


\displaystyle (-10-z)/(y) =x

Solving for j:


\displaystyle h-(4)/(j) =k

Subtracting h from both sides:


\displaystyle - (4)/(j) =-h+k

Multiplying both sides by j,

then dividing both sides by (-h + k):


\displaystyle - (4)/(-h+k) =j

Simplifying the equation:


\displaystyle (4)/(-(-h+k)) =j


\displaystyle (4)/(h-k) =j


\rule[225]{225}{2}

User Adrian Wible
by
7.7k points
4 votes

Answer:


x=(-10-z)/(y)

Explanation:

1 Subtract z from both sides.


-10-z=xy

2 Divide both sides by y


(-10-z)/(y) =x

3 Switch sides.


x=(-10-z)/(y)

2nd question

Answer:
j=-(4)/(k-h)

Explanation:

1 Subtract h from both sides


-(4)/(j) =k-h

2 Multiply both sides by j.


-4=(k-h)j

3 Divide both sides by k−h.


-(4)/(k-h)=j

4 Switch sides.


j=-(4)/(k-h)

User Wes Cossick
by
7.6k points

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