Question

1. -10=xy+z, solve for x please? 2. h-4/j =k, solve for j please?​

Answer 1

`\huge \boxed{x= (-10-z)/(y) } \\\\\\\\ \huge \boxed{j=(4)/(h-k) }`

`\rule[225]{225}{2}`

Explanation:

Solving for x:

`-10=xy+z`

Subtracting z from both sides:

`-10-z=xy`

Divding both sides by y:

`\displaystyle (-10-z)/(y) =x`

Solving for j:

`\displaystyle h-(4)/(j) =k`

Subtracting h from both sides:

`\displaystyle - (4)/(j) =-h+k`

Multiplying both sides by j,

then dividing both sides by (-h + k):

`\displaystyle - (4)/(-h+k) =j`

Simplifying the equation:

`\displaystyle (4)/(-(-h+k)) =j`

`\displaystyle (4)/(h-k) =j`

`\rule[225]{225}{2}`

Answer 2

`x=(-10-z)/(y)`

Explanation:

1 Subtract z from both sides.

`-10-z=xy`

2 Divide both sides by y

`(-10-z)/(y) =x`

3 Switch sides.

`x=(-10-z)/(y)`

2nd question

Answer:
`j=-(4)/(k-h)`

Explanation:

1 Subtract h from both sides

`-(4)/(j) =k-h`

2 Multiply both sides by j.

`-4=(k-h)j`

3 Divide both sides by k−h.

`-(4)/(k-h)=j`

4 Switch sides.

`j=-(4)/(k-h)`