Answer:
A
Explanation:
So we want an equation that is parallel to:
![y=-4x+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/f0kzuhe15vitb76ytmyvzxjkhtu7y0w2cn.png)
And passes through:
![(-3,2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yirat8fmdoy6p96t6cidq33wjj3pfzir2m.png)
First, since we want the equation to be parallel to the first, the slope must be -4. This is because parallel lines have the same slope.
Now that we know the slope of our equation is -4, we can use the point-slope form to figure out the rest.
The point-slope form is:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ks7lzc9jj3emt3ptrdvrvr0uzhz4c0qyo5.png)
m is -4. Let (-3,2) be x₁ and y₁. Thus:
![y-2=-4(x--3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/etx3olfj5xev72lucvm9xmk03gkqd5sq06.png)
Simplify:
![y-2=-4(x+3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ip9zh8w9xxtgdmt2rs2eypdd1z8jscvqhy.png)
Distribute:
![y-2=-4x-12](https://img.qammunity.org/2021/formulas/mathematics/high-school/nlf0xu4q8fdmi40ceflwy7rvkq6himv2rr.png)
Add 2 to both sides:
![y=-4x-10](https://img.qammunity.org/2021/formulas/mathematics/high-school/7q2jobdkgo9ezooeo0yp9q5dq512wrkzuy.png)
So our answer is A :)