Answer:
![x=6/13](https://img.qammunity.org/2021/formulas/mathematics/high-school/c242qks2g3zq5oq0hn7zm2sk73g2wlq6h8.png)
Explanation:
So we have:
![(2)/(3)x+(3)/(7)=1-(4)/(7)x](https://img.qammunity.org/2021/formulas/mathematics/high-school/9x9r9qfwnl0hgvgc6pe8wj91wouj4ybwks.png)
Remove all the fractions to make things simpler. To do so, we can multiply by the LCM of the denominators.
The denominators are 3 and 7.
The LCM of 3 and 7 is 21. Thus, multiply everything by 21:
![21((2)/(3)x+(3)/(7))=21(1-(4)/(7)x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/z3fw4qk2me57c36wfo4di8rmab68fnar13.png)
Distribute:
![(42)/(3)x+(63)/(7)=21-(84)/(7)x](https://img.qammunity.org/2021/formulas/mathematics/high-school/uqhte5oeydn64th7bssa3t9qddp1esc3iy.png)
Simplify the fractions:
![14x+9=21-12x](https://img.qammunity.org/2021/formulas/mathematics/high-school/kv26fn0t0tljf511qh4iaud2hfpm96tt02.png)
Add 12x to both sides:
![26x+9=21](https://img.qammunity.org/2021/formulas/mathematics/high-school/mtmkctfa42cn9vvfdaquoxheqw2zt80xk5.png)
Subtract 9 from both sides:
![26x=12](https://img.qammunity.org/2021/formulas/mathematics/high-school/lojwtpr4gkftn8q3h8uqt9s1021l8llcbu.png)
Divide both sides by 26:
![x=12/26](https://img.qammunity.org/2021/formulas/mathematics/high-school/5jh9j91fntfc834kiaxcz8leg1mln6e2ie.png)
Reduce:
![x=6/13](https://img.qammunity.org/2021/formulas/mathematics/high-school/c242qks2g3zq5oq0hn7zm2sk73g2wlq6h8.png)
And that's our answer :)