Answer:
![= 4.21* 10^(-10)J/cm^4](https://img.qammunity.org/2021/formulas/physics/high-school/zcx2g2in30tse2on46a7p2vzocw1pk7ly4.png)
Step-by-step explanation:
According to the given situation, the computation is shown below:-
![1kPa=10^3Pa](https://img.qammunity.org/2021/formulas/physics/high-school/ep5mdudy49rd5j0bvmq15np0kceadyeu1o.png)
So,
![1Km = 10^5cm](https://img.qammunity.org/2021/formulas/physics/high-school/guibgmpk0f0yieymxxpdmfnnty3aevfapu.png)
![1kPa=0.01Pa/Cm](https://img.qammunity.org/2021/formulas/physics/high-school/y79mp6cmgqf9xzxr04ihpknnx2j1afe1gp.png)
![1kPa=10^(-8)J/cm^4](https://img.qammunity.org/2021/formulas/physics/high-school/kclfb80e4733kw1zk6pnb0vcxo2ac90ffa.png)
Now as per the question it is given that
r = 0.0421KPa/Km
=
![0.0421KPa/Km * (10^(-8)J/cm^4)/(1KPa/Km)](https://img.qammunity.org/2021/formulas/physics/high-school/bo88c868jl34wdy8zjxiu38v2pjje3p347.png)
after solving the above equation we will get
=
![0.0421* 10^(-8)J/cm^4](https://img.qammunity.org/2021/formulas/physics/high-school/sij5pvgsubfvwj9ogz1ri7lscgfiecm9pv.png)
or we can write the above equation in this manner, that is
![= 4.21* 10^(-10)J/cm^4](https://img.qammunity.org/2021/formulas/physics/high-school/zcx2g2in30tse2on46a7p2vzocw1pk7ly4.png)
Therefore we have solved the equation to reach the right answer.