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What is an equation of the line that passes through the point (-4, -7) and is

parallel to the line 3x-Y = 4?

User Vees
by
7.1k points

1 Answer

1 vote

Answer:

The answer is


y = 3x + 5

Explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the line parallel to 3x - y = 14 we must first find the slope of 3x - y = 14.

So we have

y = 3x - 14

Comparing with the general equation above

Slope / m = 3

Since the lines are parallel their slope are also the same

So slope of parallel line = 3

Equation of the line using point ( - 4 , -7) and slope 3 is


y + 7 = 3(x + 4) \\ y + 7 = 3x + 12 \\ y = 3x + 12 - 7

We have the final answer as


y = 3x + 5

Hope this helps you

User Johannes Klug
by
7.9k points

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