Question

What is an equation of the line that passes through the point (-4, -7) and is

parallel to the line 3x-Y = 4?

Answer 1

The answer is

`y = 3x + 5`

Explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the line parallel to 3x - y = 14 we must first find the slope of 3x - y = 14.

So we have

y = 3x - 14

Comparing with the general equation above

Slope / m = 3

Since the lines are parallel their slope are also the same

So slope of parallel line = 3

Equation of the line using point ( - 4 , -7) and slope 3 is

`y + 7 = 3(x + 4) \\ y + 7 = 3x + 12 \\ y = 3x + 12 - 7`

We have the final answer as

`y = 3x + 5`

Hope this helps you