Answer:
The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.
Step-by-step explanation:
Power is the rate of change of work in time, since given input is average power, the total energy (
) of the motor of the electric vehicle, measured in joules, is determined by this formula:
![\Delta E = \dot W \cdot \Delta t](https://img.qammunity.org/2021/formulas/engineering/college/65uf4srscsptddayagvm8ncmw8y8c5w2w4.png)
Where:
- Average power, measured in watts.
- Time, measured in seconds.
Now, let convert average power and time into watts and seconds, respectively:
Average Power
![\dot W = (50\,hp)* (746\,W)/(1\,hp)](https://img.qammunity.org/2021/formulas/engineering/college/8lx36lsad5bmhn7lc92g07hbiv8a3q99g9.png)
![\dot W = 3.730* 10^(4)\,W](https://img.qammunity.org/2021/formulas/engineering/college/y7y6vx5oxp4b97dwv9k3xlbyntq3tu1xcs.png)
Time
![\Delta t = (1\,h)* (3600\,s)/(1\,h) + (25\,min)* (60\,s)/(1\,min)](https://img.qammunity.org/2021/formulas/engineering/college/z2aqlbed61f8ohrc6pmab865poxt0w6826.png)
![\Delta t = 5.100* 10^(3)\,s](https://img.qammunity.org/2021/formulas/engineering/college/p38nuvmpay88y761ifthgbcwm0wb3azrz1.png)
Then, the total energy is:
![\Delta E = (3.730* 10^(4)\,W)\cdot (5.100* 10^(3)\,s)](https://img.qammunity.org/2021/formulas/engineering/college/riuryf1g79sfex3agpnmq5i2q8o346of9f.png)
![\Delta E = 1.902* 10^(8)\,J](https://img.qammunity.org/2021/formulas/engineering/college/e0fk4zizmw3gkw1jbovahd9unk2h85mm76.png)
The total energy of the motor of the electric vehicle is 1.902 × 10⁸ joules.