Question

Janine completed 36 math problems. Craig completed 9 math problems. The number of problems that Janine completed is how many times the number of problems that Craig completed?

Answer 1

4 times

Explanation:

Because 36 divided by 9 = 4

So your answer is 4 times the number of problems.

Answer 2

Divide the number Janine did by the number Craig did:

36/9 = 4

Janine did 4 times as many as Craig