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Janine completed 36 math problems. Craig completed 9 math problems. The number of problems that Janine completed is how many times the number of problems that Craig completed?

2 Answers

2 votes

Answer:

4 times

Explanation:

Because 36 divided by 9 = 4

So your answer is 4 times the number of problems.

User Nitin Patel
by
6.5k points
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Divide the number Janine did by the number Craig did:

36/9 = 4

Janine did 4 times as many as Craig

User Indrit Kello
by
6.8k points
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