Question

What are the solutions to the equation? 4x ^ 3 = 36x

Answer 1

4x^3=36x.

4x^3-36x=0.

4x^3=36x.

4x(x^2-9)=0.

4x=0,x^2-9=0.

x=0,x^2=9.

x=0,√9=+3 or -3.

x=0,+3,-3.

Thank you for the question

Answer 2

x = - 3, x = 0, x = 3

Explanation:

Given

4x³ = 36x ( subtract 35x from both sides )

4x³ - 36x = 0 ← factor out 4x from each term

4x(x² - 9) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x² - 9 = 0 ⇒ x² = 9 ⇒ x = ±
`√(9)` = ± 3