Question

Find the mean, median, and range of the data. 7, 8, 9, 9, 9,9, 10, 10, 10, 11, 12, 12

Answer 1

Answer : Mean = 116
Median=10
Range=5

Answer 2

`\huge\text{Hey there!}`

`\large\textsf{QUICK RUNDOWN WHAT EACH WORD MEANS}\downarrow\\\\\bullet\large\text{ Mean}\rightarrow\large\text{ is the average/total.}\\\bullet\large\text{ Median}\rightarrow\large\text{is the number in the middle/center.}\\\bullet\large\text{ Range}\rightarrow\large\text{The dissimilarity between the smallest \& biggest number.}`

`\large\text{Data set: \bf 7, 8, 9, 9, 9,9, 10, 10, 10, 11, 12, \& 12}`

`\huge\textbf{MEAN}`

`\text{Equation:\ }\rm{(7 + 8 + 9 + 9 + 9+9+10+10+10+11+12+12)/(12)}\\\\\rm{7 + 8 + 9 + 9 + 9+9+10+10+10+11+12+12}\\\rm{= 15 + 9 + 9 + 9 + 9 + 10 + 10 + 10 + 11 + 12 + 12}\\\rm{= 33 + 9 + 9 + 10 + 10 + 10 + 11 + 12 + 12}\\\rm{= 42 + 9 + 10 + 10 + 10 + 11 + 12 + 12}\\\rm{= 51 + 10 + 10 + 10 + 11 + 12 + 12}\\\rm{= 61 + 10 + 10 + 11 + 12 + 12}\\\rm{= 71 + 10 + 11 + 12 + 12}\\\rm{= 81 + 11 + 12 + 12}\\\rm{= 92 + 12 + 12}\\\rm{= 104 + 12}\\\rm{= 116}\\\\\text{NEW EQUATION: }\rm{(116)/(12)}`

`\text{SIMPLIFY IT!}\\\\\rm{\approx 9.6666666666667}`

`\huge\textbf{MEDIAN}`

`\text{10 because ten is the middle/center number of the data plot.}`

`\huge\textbf{Range}`

`\text{Largest: 12}\\\text{Smallest: 7}\\\\\text{Equation: }\rm{12 - 7}\\\text{SIMPLIFY IT!}\\\rm{= 5}`

`\huge\text{Therefore, your answer is: }\\\huge\boxed{\mathsf{\bullet \ Mean: 9.6666666666667}} \\\huge\boxed{\mathsf{\bullet \ Median: 10}}\\\huge\boxed{\mathsf{\bullet Range: \ 5}}`

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`\frak{Amphitrite1040:)}`