194k views
3 votes
An helicopter lowers a probe into lake Chad which is suspended on a cable. the probe has a mass of 500kg and its average density is 1400kg/m³. what is the tension in the cable?​

1 Answer

3 votes

Answer:

1,401.85N

Step-by-step explanation:

If the mass of the probe is 500kg, its weight W = mass acceleration due to gravity.

Weight of the probe = 500*9.81

Weight of the probe = 4,905N

If its average density = 1400kg/m³

Volume = Mass/Density

Volume = 500/1400

Volume = 0.3571m³

According to the floatation principle, the volume of the probe is equal to the volume of liquid displaced. Hence the volume of water displaced is 0.357m³.

Since density of water is 1000kg/m³, we can find the mass of the water using the formula;

Mass of water = Density of water * Volume of water

Mass of water = 1000*0.3571

Mass of water = 357.1kg

Weight of water displaced = 3571 * 9.81 = 3503.15N

The tension in the cable will be the difference between the weight of the probe and weight of the displaced fluid.

Tension in the cable = 4,905N - 3503.15N

Tension in the cable = 1,401.85N

Hence the tension in the cable is 1,401.85N

User Marrossa
by
5.5k points