Question

What is the normality of 500ml
Solution of Sodium hydroxide Containing 30 gm naoh?​

Answer 1

`N=1.5N`

Step-by-step explanation:

Hello,

In this case, since normality is defined in terms of the equivalent grams and the volume of the solution:

`N=(eq-g)/(V)`

We need to compute the equivalent grams by considering that the molar mass of NaOH is 40 g/mol and one mole of NaOH contains one equivalent grams due to the presence of one hydroxyl ion only:

`eq-g=30gNaOH*(1molNaOH)/(40gNaOH) *(1eq-g)/(1mol)=0.75eq-g`

And the volume in liters (0.500 L). Therefore, we obtain:

`N=(0.75eq-g)/(0.500L) \\\\N=1.5N`

Regards.