Question

A. where does the parentheses go in 8+9÷3×6-5 to make a value of 11

b. where does the parentheses go in 5+3-8÷4-2 to make a total of 4 ​

Answer 1

• 8+9÷3×(6-5)
• 5+3-8÷4-2

Explanation:

`8+9/3*6-5\\= 8+9/ \:3* \left(6-5\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(6-5\right)\::\quad 1\\=8+9/ \:3* \:1\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:9/ \:3* \:1\::\quad 3\\=8+3\\\\= 11`

`5+3-8/ \:4-2\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:8/ \:4\::\quad 2\\=5+3-2-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:5+3-2-2\::\quad 4\\=4`

`\left(5+3\right)-8/ \:4-2\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5+3\right)\::\quad 8\\=8-8/ \:4-2\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:8/ \:4\::\quad 2\\=8-2-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:8-2-2\::\quad 4\\=4`