38.5k views
3 votes
A. where does the parentheses go in 8+9÷3×6-5 to make a value of 11

b. where does the parentheses go in 5+3-8÷4-2 to make a total of 4 ​

User LYu
by
7.7k points

1 Answer

6 votes

Answer:

  • 8+9÷3×(6-5)
  • 5+3-8÷4-2

Explanation:


8+9/3*6-5\\= 8+9/ \:3* \left(6-5\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(6-5\right)\::\quad 1\\=8+9/ \:3* \:1\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:9/ \:3* \:1\::\quad 3\\=8+3\\\\= 11


5+3-8/ \:4-2\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:8/ \:4\::\quad 2\\=5+3-2-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:5+3-2-2\::\quad 4\\=4


\left(5+3\right)-8/ \:4-2\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5+3\right)\::\quad 8\\=8-8/ \:4-2\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:8/ \:4\::\quad 2\\=8-2-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:8-2-2\::\quad 4\\=4

User Melc
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories