Answer:
C
Explanation:
When completing the square, we essentially want to create a perfect square trinomial by adding a constant.
If we have the following expression:
![x^2+bx](https://img.qammunity.org/2021/formulas/mathematics/high-school/jaq6xrv5vhahks0kcw0q7s2grpujw20adv.png)
And we want to complete the square, we will need to divide the b-coefficient by half and then square it.
Thus, the added term should be:
![(b/2)^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/qdtissw6bdyzp5mzuinc1tte8ibvev9946.png)
In the given equation, we have:
![(x^2-8x)-10](https://img.qammunity.org/2021/formulas/mathematics/high-school/p2mv7vs0kqnn0awlpc6z0fm100bj8d1jat.png)
The b term here is 8. Therefore:
![(8/2)^2\\=(4)^2\\=16](https://img.qammunity.org/2021/formulas/mathematics/high-school/2s4s4it5bvl8myt6zq8rrs5is5rfk7xtvt.png)
The value we would add would be 16.
The answer is C.
Further notes:
To complete the square, add 16 like mentioned earlier. However, we also need to subtract 16 to balance things out:
![(x^2-8x)-10\\=(x^2-8x+16)-10-16\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/7xb40h0uk4koaa6oivzw7cxnyya39n1d4r.png)
The expression inside the parentheses is now a perfect square trinomial. Factor it:
![=((x)^2-2(4)(x)+(4)^2)-26\\=(x-4)^2-26](https://img.qammunity.org/2021/formulas/mathematics/high-school/jpc0p4r5o4lxif3nl7iikocc4f9lrqg3ru.png)
And we are done!