140,270 views
37 votes
37 votes
Can someone teach me how to do this?
no files or links please

Can someone teach me how to do this? no files or links please-example-1
User David Hol
by
2.5k points

1 Answer

16 votes
16 votes

Check the picture below.

we know the box has a square base, meaning the Length = Width, we also know its volume is 400 times its height.


\textit{volume of a rectangular prism}\\\\ V=Lwh~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=h+12\\ w=h+12\\ V=400h \end{cases}\implies 400h=(h+12)(h+12) \\\\\\ 400h=\stackrel{F~O~I~L}{h^2+24h+144}\implies 0=h^2+24h-256 \\\\\\ 0=(h-8)(h+32)\implies h= \begin{cases} 8~~\checkmark\\ -32 \end{cases}

now, notice, -32 is a valid value for "h", however, the height cannot be a negative value, so we toss that root/solution.


\stackrel{height}{8}\qquad \qquad \underset{8~~ + ~~12}{\stackrel{length}{20}}\qquad \qquad \underset{8~~ + ~~12}{\stackrel{width}{20}}

Can someone teach me how to do this? no files or links please-example-1
User Mohamed Elbou
by
3.0k points
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