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A cylindrical can of radius R is rolling across a horizontal surface without slipping. A. After one complete revolution of the can, what is the distance that its center of mass has moved. B. Would this
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A cylindrical can of radius R is rolling across a horizontal surface without slipping.

A. After one complete revolution of the can, what is the distance that its center of mass has moved.
B. Would this distance be greater or smaller if slipping occurred?

User BrMcMullin
by
4.7k points

1 Answer

3 votes

Answer:

a) 2πR

b) greater

Step-by-step explanation:

Radius of the cylinder = R

a) after one complete revolution, the center of mass would have moved a distance equal to the circumference of the radius formed by the cylinder.

distance moved = 2πR

b) If slipping occurred, there will be some distance lost during rotation, which will increase the distance that the center of mass will have to move.

User Pplonski
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