X^2 -9 divided by x+3

Question

asked Jan 3, 2021 82.1k views

1 Answer

James Koppel · Answer 1 · 2021-01-09T22:44:20+0000

Explanation:

Hey, there!!

Given that,

$\frac{ {x}^(2) - 9 }{x + 3}$

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

$\frac{ {x}^(2) - {3}^(2) }{x + 3}$

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

(x+3) in numerator and denominator gets cancelled,

Therefore, (x-3) is the final value.

Hope it helps...