Question

Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately Normally distributed with a mean of 2.45 microns and a standard deviation of 0.35 micron. What position, in microns, are 20% of binding sites greater than

Answer 1

2.74 microns

Explanation:

According to the given situation, the calculation of position, in microns, is shown below:-

Here we will use the standard normal table,

P(Z > z) = 20%

1 - P(Z < z) = 0.2

P(Z < z) = 1 - 0.2

P(Z < 0.84) = 0.8

after solving the above equation we will get

z = 0.84

Now we will use the z-score formula,

`x = z * \sigma + \mu`

`x = 0.84 * 0.35 + 2.45`

x = 0.294 + 2.45

= 2.744 microns

or

= 2.74 microns