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What are the domain and range of this function y=(x+3)^2 -5

a. domain: (-∞, ∞) range: (-5, ∞)
b. domain: (-∞, ∞) range: (-∞, ∞)
c. domain: (-5, ∞) range: (-5, ∞)
d. domain: (-5, ∞) range (-∞, ∞)

User KEYSAN
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2 Answers

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Option A is the correct choice .

Domain will be all real numbers .

Range will be y belongs to R : y greater than or equal to -5 .

→ (x+3)^2 It means 0 to infinity

So (x+3)^2-5= (-5, infinity)

→ Range = (-5, infinity )

What are the domain and range of this function y=(x+3)^2 -5 a. domain: (-∞, ∞) range-example-1
User Zarina
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Answer: Choice A

Note: the range should be
[-5, \infty). See explanation below.

===================================================

We can plug in any real number for x to get some output for y. The domain is the set of all real numbers in which we say
(-\infty, \infty) which is interval notation. It represents the interval from negative infinity to positive infinity.

The range is the set of possible outputs. The smallest output possible is y = -5 which occurs at the vertex (3,-5). We can get this y value or larger. So we can describe the range as the set of y values such that
y \ge -5 and that translates to the interval notation
[-5, \infty).

The square bracket says "include this endpoint" while the curved parenthesis says to exclude the endpoint. Your teacher mistakenly wrote
(-5, \infty) for choice A, when they should have written
[-5, \infty)

I think either your teacher made a typo or somehow the formatting messed up. Either way, choice A is the closest to the answer.

User Slosd
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