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Two charges of +4x10-SC and -4x10-5C are placed 1 meter apart. Using Coulomb's law, the force between them is 14.4 N. If the distance between the two charges is doubled to 2 m, what happens to the force
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Two charges of +4x10-SC and -4x10-5C are placed 1 meter apart. Using Coulomb's law, the force between them is 14.4 N.

If the distance between the two charges is doubled to 2 m, what happens to the force between the two charges?

A. the force is reduced by one-half to 7.2 N
B. the force increases four times to 57.6 N
C. the force remains the same
D. the force is reduced by one quarter to 3.6

User Hasan Bou Taam
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1 Answer

8 votes

Answer:

d. the force is reduced by one quarter to 3.6 n

Step-by-step explanation:

Two charges of +4x10-SC and -4x10-5C are placed 1 meter apart. Using Coulomb's law-example-1
User Ladislas Nalborczyk
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5.3k points
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