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20 points! Thanks for the help :)

20 points! Thanks for the help :)-example-1

2 Answers

7 votes

Answer:


-2x^6+7x^4+3x^3-3x^2+11x+20

Explanation:

a) We can expand
(-2x^3 + x - 5) (x^3 - 3x - 4), getting
-2x^6+6x^4+8x^3+x^4-3x^2-4x-5x^3+15x+20. We can then combine like terms, getting
-2x^6+7x^4+3x^3-3x^2+11x+20.

b) Yes it is the same, as it doesn't matter the order if you multiply two polynomials. It will always be the same.

User Andrei Taranchenko
by
8.9k points
6 votes

Answer:

Explanation:

a) (-2x³ + x - 5)(x³ - 3x - 4)

= (-2x³) (x³ - 3x - 4) + x(x³ - 3x - 4) - 5(x³ - 3x - 4)

= -2x³*x³ - (-2x³)*3x - (-2x³)*4 + x*x³ - x*3x - x*4 + x³ * (-5) - 3x*(-5) -4*(-5)

= -2x⁶ + 6x⁴ + 8x³ + x⁴ - 3x² -4x - 5x³ + 15x + 20 {add like terms}

= -2x⁶ + 6x⁴ + x⁴ + 8x³ - 5x³ - 3x² - 4x + 15x + 20

= -2x⁶ + 7x⁴ + 3x³ - 3x² + 11x + 20

Hint: When multiplying two terms, multiply the coefficient, and add the powers of the variables {
a^(m)*a^(n)=a^(m+n) }

-2x³*x³ = (-2*1) *
x^(3+3) = -2x⁶

b) Yes , same because of commutative property of multiplication

User Mukund
by
7.4k points

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