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Solv for x for all of these 1. 3x+6=21 2. 33=7x-9 3. 28=7+x need to know now please help !!!!!!

User SPSN
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1 Answer

2 votes

Answer:


\boxed{ \sf{ \bold{1. \: \: \: x = 5}}}


\boxed{ \sf{ \bold{2. \: \: x = 6}}}


\boxed{ \bold{ \sf{3. \: \: x = 21}}}

Explanation:

1.
\sf{3x + 6 = 21}

Move constant to right hand side and change its sign


\sf{3x = 21 - 6}

Subtract 6 from 21


\sf{3x = 15}

Divide both sides of the equation by 3


\sf{ (3x)/(3) = (15)/(3) }

Calculate


\sf{x = 5}

--------------------------------------------------------

2.
\sf{33 = 7x - 9 }

Swap the sides of the equation


\sf{7x - 9 = 33}

Move constant to right hand side and change it's sign


\sf{7x = 33 + 9}

Add the numbers


\sf{7x = 42}

Divide both sides of the equation by 7


\sf{ (7x)/(7) = (42)/(7) }

Calculate


\sf{x = 6}

---------------------------------------------------------

3.
\sf{28 = 7 + x}

Swap the sides of the equation


\sf{7 + x = 28}

Move constant to right hand side and change it's sign


\sf{x = 28 - 7}

Subtract 7 from 28


\sf{x = 21}

Hope I helped!

Best regards!!

User Janderssn
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