Question

In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separation between adjacent bright fringes on a screen 5 m from the slits is: CONVERT FIRST

Answer 1

The value is
`y = 0.0025 \ m`

Step-by-step explanation:

From the question we are told that

The wavelength is
`\lambda = 500 \ nm`

The distance of separation is
`d = 1\ mm = 0.001 \ m`

The distance from the screen is
`D = 5 \ m`

Generally the separation between the adjacent bright fringe is mathematically represented as

`y = (D * \lambda )/( d)`

=>
`y = (5 * 500 *10^(-9))/(0.001)`

=>
`y = 0.0025 \ m`