Question

Find the error (-8x^2y^2)^2= -64x^4y^4

Answer 1

64 shouldnt be negative anymore

Explanation:

(-8x^2y^2)^2 = -64x^4y^4

when exapnding the left side it would be...

(-8x^2y^2)^2

Apply exponent rule (-a)^n = a^n

→ (8x^2y^2)^2

→ (8^2)(x^2)^2

→ (8^2) = 64

→ 64(x^2)^2 = 64x^4

Hope this helps. Let me know if you have any questions !

Have a nice rest of you day :)

Answer 2

`(-8)^2\\eq-64`

Explanation:

Using the distributive property to expand, we have

`(-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.`

Squaring each term, we have

`(-8x^2y^2)^2=64x^4y^4.`

The mistake was that
`8^2=64,` not
`-64.` Using the fact that
`8^2=64,` the right answer would be

`\boxed{64x^4y^4}`.