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Evaluate R C F · dr, where F(x, y, z) = 5xi − 5yj − 3zk and C is given by the vector function r(t) = hsin t, cost, ti, where 0 ≤ t ≤ π.

1 Answer

7 votes

Answer:


\mathbf{ - (3 \pi^2)/(2)}

Explanation:

Given that:

F(x, y, z) = 5xi - 5yj - 3zk

The objective is to evaluate the
\int _c F \ dr .C

and C is given by the vector function r(t) = (sin t, cost, t) where 0 ≤ t ≤ π


F(r(t)) = 5 \ sint \ i - 5 \ cost \ j - 3t \ k


\int_c F . \ dr = \int ^(\pi)_(0) ( 5 \ sint \ i - 5 cos t \ j - 3 t \ k ) ( cos \ t , - sin \ t , 1 ) \ dt


=\int ^(\pi)_(0) ( 5 \ sint \ cost+ 5 cos t \ sin t - 3 t) dt


=\int ^(\pi)_(0) ( 10 \ sint \ cost) \ dt -3 \int ^(\pi)_(0) \ dt


= \int ^(\pi)_(0) ( 10 \ sint \ cost) \ dt - 3 [\frac {t^2}{2}]^(\pi)_(0) \ \ dt


= 10 [(sin^2 \ t)/(2)]^(\pi)_(0) - (3)/(2)(\pi)^2

By dividing 2 with 10 and integrating
= 10 [(sin^2 \ t)/(2)]^(\pi)_(0); we have:


=5(sin^2t -sin^2 0) -(3 \pi^2)/(2)


=5(0) -(3 \pi^2)/(2)


= 0 - (3 \pi^2)/(2)


\mathbf{= - (3 \pi^2)/(2)}

User Mgriebe
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