Question

You wish to prepare 222 grams of 22.1 % FeCl2. You will need_______ grams of iron(II) chloride and ________mL of water. Assume that the density of water is 1.00 g / ml

Answer 1

same

Step-by-step explanation:

confused

Answer 2

I will need 49 grams of iron(II) chloride and 173 mL of water .

Step-by-step explanation:

222 grams of 22.1 % FeCl₂ will require

222 x 0.221 gram of FeCl₂ and rest will be water .

49 gram of FeCl₂ and 173 grams of water .

density of water is 1.00 g / mL

volume of water in mL = 173 / 1

= 173 mL

Hence I will need 49 grams of iron(II) chloride and 173 mL of water .