Answer:
Coordinates of the starting point ( -50 ; 0 )
Coordinates 4 seconds later Q ( - 25*√3 ; 25 )
Coordinates 32 seconds later R ( 25 ; - 25*√3 )
Explanation:
a) If Jeremy takes 48 seconds fr a lap then
The length of the lap ( length of the circle ) is:
L = 2*π*r ⇒ L = 100*π
If the time for one lap was 48 seconds at a constant speed, the speed was
v = 100*π / 48 [m/s]
v = 6,54 m/s
12 seconds is 1/4 0f 48 in that time he (she) reach the northernmost point, then he(she) necessarily started on the negative side of the x-axis the coordinates at this point are
( -50 ; 0 )
b) 4 seconds later, at v = 6,54 m/s by rule of three
In 12 seconds 90⁰
In 4 seconds (the third part ) x ??
x = 30⁰
sin 30⁰ = 1/2
cos 30⁰ = (√3)/2
And coordinates for the point are
sin 30⁰ = 1/2 = y/50 ⇒ y = 25
cos 30⁰ = (√3)/2 = x / 50 ⇒ x = 25*√3
coordinates of the point 4 seconds later
Q ( - 25*√3 ; 25 ) she (he) is in the negative part of x-axis
c) 32 seconds later
32 is 12 + 12 + 8
Then she (he) is 8 seconds below the positive side of x-axis
8 is 2/3 of 12 ( negative 60⁰ )
sin 60⁰ = (√3)/2 = y/50 y = 25*√3 negative
cos 60⁰ = 1/2 * 50 = X/50 x = 25
Coordinates of the point R
R ( 25 ; - 25*√3 )