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1 vote
An object on the end of a spring is oscillating in simple harmonic motion. If the amplitude of oscillation is doubled, how does this affect the object’s maximum speed?

User Bwyss
by
7.7k points

2 Answers

3 votes

Answer:

The amplitude decreased as the stiffness of the spring increased.

Step-by-step explanation:

User Brian Ferris
by
8.3k points
6 votes

Answer:

The maximum speed of the oscillating object doubles as well.

Step-by-step explanation:

The oscillatory motion of the object on the spring can be modelled using this equation below:


Vmax= A\omega

Where

Vmax = the maximum speed of the oscillating object.

A = Amplitude of the oscillating object.


\omega = angular velocity of the oscillating object.

If the amplitude, A becomes doubled, the new amplitude will be = 2A.

As a result,
Vmax = 2 A \omega

This shows that the maximum speed has doubled in its value

User Roma Rush
by
8.2k points
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