Question

An object on the end of a spring is oscillating in simple harmonic motion. If the amplitude of oscillation is doubled, how does this affect the object’s maximum speed?

Answer 1

The amplitude decreased as the stiffness of the spring increased.

Step-by-step explanation:

Answer 2

The maximum speed of the oscillating object doubles as well.

Step-by-step explanation:

The oscillatory motion of the object on the spring can be modelled using this equation below:

`Vmax= A\omega`

Where

Vmax = the maximum speed of the oscillating object.

A = Amplitude of the oscillating object.

`\omega` = angular velocity of the oscillating object.

If the amplitude, A becomes doubled, the new amplitude will be = 2A.

As a result,
`Vmax = 2 A \omega`

This shows that the maximum speed has doubled in its value