Question

What is the molar mass of butane if 4.49 x 1016 molecules of butane weigh 8.29?

Answer 1

Answer: The molar mass of butane will be
`11.2* 10^(7)g`

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP, contains avogadro's number
`6.023* 10^(23)` of particles. and weighs equal to the molar mass.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=(4.49* 10^(16))/(6.023* 10^(23))=0.74* 10^(-7)moles`

Now
`0.74* 10^(-7)moles` weigh = 8.29 g

Thus 1 mole will weigh =
`(8.29)/(0.74* 10^(-7))* 1=11.2* 10^(7)g`

The molar mass of butane will be
`11.2* 10^(7)g`