1 Answer

Exoslav · Answer 1 · 2021-07-02T13:41:43+0000

Answer:

$\boxed{\sf Time \ taken = 10 \ seconds}$

Given:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Acceleration (a) = 2 m/s²

To Find:

Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s²

Step-by-step explanation:

$\sf From \ equation \ of \ motion:$

$\boxed{ \bold{v = u + at}}$

Substituting values of v, u & a in the equation:

$\sf \implies 30 = 10 + 2t$

Substract 10 from both sides:

$\sf \implies 30 - 10 = (10 - 10) + 2t$

$\sf \implies 20 = 2t$

20 = 2t is equivalent to 2t = 20:

$\sf \implies 2t = 20$

Dividing both sides by 2:

$\sf \implies \frac{ \cancel{2}t}{ \cancel{2}} = (20)/(2)$

$\sf \implies t = \frac{10 * \cancel{2}}{ \cancel{2}}$

$\sf \implies t = 10 \: s$

So,

Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s² = 10 seconds

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