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Find the absolute extrema of the function on the closed interval. f(x) = sin 2x, [0, 2π]

User Melpomene
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1 Answer

4 votes

Answer:

Minimum -1, maximum 1.

At points (3π/4. -1) and (π/4 , 1)

Explanation:

The maximum value for the sine of an angle is 1 and the minimum is -1.

The angle will have values of π/2 and 3π/2 at these points.

As the angle is 2x the angle values will be π/4 and 3π/4.

User Ed Mozley
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